Perfect. Thanks. To understand:
(\d+)E searches for all numbers that are followed by the capital E.
(If I leave Replace "Clear", that would remove "2002E", for example).
$1P means that once it finds that string, it should only replace the next character. If I had done $2, it would have replaced two characters, etc.
Yes?
What if, for example, I wanted to replace just the last digit?
So 2002E => 200xE, 2003E => 200xE, etc.
Playing around and can't quite figure it out.
(\d+)E searches for all numbers that are followed by the capital E.
(If I leave Replace "Clear", that would remove "2002E", for example).
$1P means that once it finds that string, it should only replace the next character. If I had done $2, it would have replaced two characters, etc.
Yes?
What if, for example, I wanted to replace just the last digit?
So 2002E => 200xE, 2003E => 200xE, etc.
Playing around and can't quite figure it out.
Statistics: Posted by Alonzo Mosley — 2024-11-01, 17:26 UTC